Simplify the expression below. 2n/6n+4 3n+2/3n-2 What is the numerator of the simplified expression?

Answer:nStep-by-step explanation:[tex](\frac{2n}{6n+4})(\frac{3n+2}{3n-2})[/tex]We see that in the first rational expression, both the numerator and denominator are divisible by 2.  This means we can factor a 2 out of the top and bottom and then cancel it:[tex](\frac{2(n)}{2(3n+2)})(\frac{3n+2}{3n-2})\\\\=(\frac{n}{3n+2})(\frac{3n+2}{3n-2})[/tex]Now we can multiply straight across:[tex]\frac{n(3n+2)}{(3n+2)(3n-2)}[/tex]Since we have the same factor on the top and bottom, this factor cancels:[tex]\frac{n}{3n-2}[/tex]The numerator is n.