(01.05) what is the slope-intercept form equation of the line that passes through (3, 4) and (5, 16)? (1 point) y = 6x − 14 y = −6x + 14 y = −6x − 14 y = 6x + 14

(3,4)(5,16)
slope = (16 - 4) / (5 - 3) = 12/2 = 6

y = mx + b
slope(m) = 6
use either of ur points (3,4)...x = 3 and y = 4
sub and find b, the y int
4 = 6(3) + b
4 = 18 + b
4 - 18 = b
-14 = b

so ur equation is : y = 6x - 14