2. Juan is flying a piscucha. He is releasing the thread, having his hand at the height of the throat, which is 1.68 meters from the ground, if the thread forms an angle of elevation of 50°, at what height is the piscucha at the moment that Juan has released 58 meters of the thread?
Question
Answer:
STEP BY STEP SOLUTION:
Let's denote:
- h as the height of the piscucha above the ground at a given moment,
- d as the distance between Juan's hand and the point directly below the piscucha (which is 58 meters since he has released 58 meters of the thread),
- a as the angle of elevation (50° in this case).
The relationship between the height h, the distance d, and the angle of elevation a can be represented by the sin function:
$$ \[ \sin(a) = \frac{h}{d} \] $$
In this scenario:
$$ \[ \sin(50°) = \frac{h}{58 \, \text{m}} \] $$
Now, solve for h:
$$ \[ h = 58 \, \text{m} \times \sin(50°) \] $$
Using a calculator:
$$ \[ h = 44.43 \, \text{meters} \] $$
ANSWER:
Therefore, at the moment Juan has released 58 meters of the thread, the piscucha is $$ \( 44.43 \, \text{meters} + 1.68 \, \text{meters} = 46.11 \, \text{meters} \) $$ above the ground.
solved
general
11 months ago
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