5x-5y/4=4x-4/2 Find the equation of the line which passes through the point (10,7) and is perpendicular to the given line. Express in slope intercept form.

Answer:Step-by-step explanation:The equation of a straight line can be represented in the slope-intercept form, y = mx + cWhere c = interceptFor two lines to be perpendicular, the slope of one line is the negative reciprocal of the other line. The equation of the given line is (5x-5y)/4= (4x-4)/2 Cross multiplying2(5x - 5y) = 4(4x - 4)10x - 10y = 16x - 1610y = - 6x + 16y = -6x/10 + 16/10Comparing with the slope intercept form,Slope, m = - 6/10This means that the slope of the line that is perpendicular to it is 10/6The given points are (10,7)To determine c,We will substitute m = 10/6, y = 7 and x = 10 into the equation, y = mx + c. It becomes7 = 10/6 × 10 + c7 = 100/6 + c7 = 50/3 + cc = 7 - 50/3c = - 29/3The equation becomesy = 10x/6 - 29/3