A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3237 tickets overall. It has sold 145 more​ $20 tickets than​ $10 tickets. The total sales are ​$62030. How many tickets of each kind have been​ sold?

Answer: $10 = 1,546 tickets sold $20 = 1,691 tickets soldStep-by-step explanation:1. Let's re-evaluate and organize our information given by the passage.PRICEReg. tickets = $10 and $20VIP​ seats = $30Tickets sold (# of all tickets) = 3,237 tickets Tickets sold OVERALL = 145 more​ $20 tickets sold than​ $10 ticketsMoney made = ​$62,0301. We need to represent x as the amount of the $10 tickets being sold, and y being the amount of $20 tickets being sold, so it'll look similarly like this: x + y ( x + 145 ) = 3,237 Remember, the number of the $10 tickets and the number of $20 tickets being sold needs to equal 3,237.2. Now, let's make estimates on what the # of tickets being for the $10 tickets is (because the # of $10 being sold affects the # of the $20 tickets being sold, and we have to start with this step first to in order find the number of $20 tickets sold).3. x = 1,000y = 1,1451,000 + 1,145= 2,145NOT 1,000 (HIGHER THAN 1,000)x = 2,000y = 2,1452,000 + 2,145 = 4,145NOT 2,000 (LOWER THAN 2,000)From these 2 estimates, the sales of x is between 1,000 and 2,000. x = 1,546y = 1,6911,546 + 1,691 = 3,237 tickets