A collection of dimes and quarters is worth $10.45. There are 70 coins in all. Find how many of each there are

There are 47 dimes and 23 quarters. Step-by-step explanation:Total amount = $10.45 = 10.45*100 = 1045 centsTotal coins = 701 dime = 10 cents1 quarter = 25 centsLet, Dimes = xQuarters = y According to given statement; x+y=70   Eqn 110x+25y=1045   Eqn 2Multiplying Eqn 1 by 10;[tex]10(x+y=70)\\10x+10y=700\ \ \ Eqn\ 3[/tex]Subtracting Eqn 3 from Eqn 2[tex](10x+25y)-(10x+10y)=1045-700\\10x+25y-10x-10y=345\\15y=345[/tex]Dividing both sides by 15;[tex]\frac{15y}{15}=\frac{345}{15}\\y=23[/tex]Putting y=23 in Eqn 1[tex]x+23=70\\x=70-23\\x=47[/tex]There are 47 dimes and 23 quarters. Keywords: linear equations, subtractionLearn more about linear equations at:brainly.com/question/12954015brainly.com/question/13018923#LearnwithBrainly