A fair coin is tossed three times in succession. the set of equally likely outcomes is startset hhh comma hht comma hth comma thh comma htt comma tht comma tth comma ttt endset. find the probability of getting exactly one head.

Solution:As Given a coin is tossed thrice.Total possible outcome = {HHH, TTT,HHT,HTH,THH,TTH,THT,HTT}=8Total Favorable outcome = Exactly one Head = {TTH, THT,HTT} = 3Probability of getting exactly one head = [tex]\frac{\text{Total favorable outcome}}{\text{Total Possible Outcome}}[/tex]           = [tex]\frac{3}{8}[/tex]