A line has a slope of -3/5 Which ordered pairs could be points on a parallel line? Check all that apply.(–8, 8) and (2, 2)(–5, –1) and (0, 2)(–3, 6) and (6, –9) (–2, 1) and (3, –2) (0, 2) and (5, 5)

we know thatThe formula to calculate the slope between two points is equal to[tex]m=\frac{y2-y1}{x2-x1}[/tex]If two lines are parallel, then their slopes are equalin this problem we havethe slope of the given line is [tex]m=-\frac{3}{5}[/tex]if ordered pairs could be points on a parallel line, then the ordered pairs must have a slope equal to [tex]m=-\frac{3}{5}[/tex]we are going to calculate the slope in each of the casescase A) [tex](-8,8)\ and\ (2,2)[/tex]substitute the values in the formula[tex]m=\frac{2-8}{2+8}[/tex][tex]m=\frac{-6}{10}[/tex][tex]m=-\frac{3}{5}[/tex][tex]-\frac{3}{5}=-\frac{3}{5}[/tex] --------> the ordered pair could be on a parallel linecase B) [tex](-5,-1)\ and\ (0,2)[/tex]substitute the values in the formula[tex]m=\frac{2+1}{0+5}[/tex][tex]m=\frac{3}{5}[/tex][tex]-\frac{3}{5} \neq \frac{3}{5}[/tex]--------> the ordered pair could not be in a parallel linecase C) [tex](-3,6)\ and\ (6,-9)[/tex]substitute the values in the formula[tex]m=\frac{-9-6}{6+3}[/tex][tex]m=\frac{-15}{9}[/tex][tex]m=-\frac{5}{3}[/tex][tex]-\frac{3}{5} \neq -\frac{5}{3}[/tex]--------> the ordered pair could not be in a parallel linecase D) [tex](-2,1)\ and\ (3,-2)[/tex]substitute the values in the formula[tex]m=\frac{-2-1}{3+2}[/tex][tex]m=\frac{-3}{5}[/tex][tex]m=-\frac{3}{5}[/tex][tex]-\frac{3}{5} =-\frac{3}{5}[/tex]--------> the ordered pair could be on a parallel linecase E) [tex](0,2)\ and\ (5,5)[/tex]substitute the values in the formula[tex]m=\frac{5-2}{5-0}[/tex][tex]m=\frac{3}{5}[/tex][tex]-\frac{3}{5} \neq \frac{3}{5}[/tex]--------> the ordered pair could not be in a parallel linethereforethe answer is[tex](-8,8)\ and\ (2,2)[/tex][tex](-2,1)\ and\ (3,-2)[/tex]