A normally distributed population has a mean of 475 and a standard deviation of 60. a. Determine the probability that a random sample of size 16 selected from this population will have a sample mean less than 435.b. Determine the probability that a random sample of size 25 selected from the population will have a sample mean greater than or equal to 501.

Answer: a. 0.0038    b. 0.0151Step-by-step explanation:Given : A normally distributed population has a mean of 475 and a standard deviation of 60.i.e. [tex]\mu=475[/tex]  [tex]\sigma=60[/tex]Let [tex]\overline{X}[/tex] be the sample mean.Formula : [tex]z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]a. For sample n= 16Then, the probability that a random sample of size 16 selected from this population will have a sample mean less than 435. will be :-[tex]P(\overline{x}<435)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}<\dfrac{435-475}{\dfrac{60}{\sqrt{16}}})\\\\\approx P(z<-2.67)\\\\=1-P(z<2.67)\ \ [\because\ P(Z<-z)=1-P(Z<z)]\\\\=1-0.9962=0.0038\ \ \ [ \text{Using z-value table}][/tex]∴ The probability that a random sample of size 16 selected from this population will have a sample mean less than 435 = 0.0038b. For sample n= 25Then, the probability that a random sample of size 16 selected from this population will have a sample mean less than 435. will be :-[tex]P(\overline{x}\geq501)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{501-475}{\dfrac{60}{\sqrt{25}}})\\\\\approx P(z\geq2.167)\\\\=1-P(z<2.167)\ \ [\because\ P(Z\geq z)=1-P(Z<z)]\\\\=1-0.9849=0.0151\ \ \ [ \text{Using z-value table}][/tex]∴ The probability that a random sample of size 25 selected from the population will have a sample mean greater than or equal to 501 = 0.0418