A student solved the following problem and made an error:Triangles ABC and DEF. Angles A and F are congruent and measure 63 degrees. Coordinates for the vertices are at A 1, 2 and B 1, 4 and C 3, 3 and D 5, 1 and E 3, 2 and F 5, 3.Line 1 segment AB equals 2, segment FD equals 2, segment AB is congruent to segment FDLine 2 ∠A ≅ ∠FLine 3 Length of segment AC.A (1, 2)C (3, 3)d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, then d equals square root of quantity 1 minus 3 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1 squared, then d equals square root of 4 plus 1, then d equals square root of 5segment AC = 2.23Line 4 Length of segment EF.E (3, 2)F (5, 3)d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared then d equals square root of quantity 3 minus 5 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1, then d equals square root of 4 plus 1, then d equals square root of 5segment EF= 2.23Line 5 segment AC is congruent to segment FELine 6 triangle ABC is congruent to triangle EFDby SASIn which line did the student make the first mistake? Line 1 Line 5 Line 6 Line 2