A toy rocket is launched from a platform 29 feet above the ground at a speed of 79 feet per second. The height of the rocket in feet is given by the polynomial −16t^2 + 79t + 29, where t is the time in seconds. How high will the rocket be after 3 seconds?
Question
Answer:
:)Height = -16t² + 79t + 29
3 sec means t = 3, we substitute t with 3
H = -16(3)² + 79(3) + 29
= -144 + 237 +29
= 122 feet
solved
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