Bax invested a total of $2000 in two simple interest accounts. Account A earns 3% interest and Account B earns 5% interest. Bax earned a total of $75 interest after one year. How much did Bax invest in each account?

Bax invested a total of $2000 in two simple interest accounts. Account A earns 3% interest and Account B earns 5% interest. Bax earned a total of $75 interest after one year. How much did Bax invest in each account?Let, The amount invested in Account A=x Then, the amount invested in Account B=2000-xThe formula of Simple Interest =[tex] \frac{Principle*Rate*Time}{100} [/tex]Interest earned in Account A in 1 year=[tex] \frac{x*3*1}{100} [/tex]Interest earned by Account A=[tex] \frac{3x}{100} [/tex]Interest earned in Account B in 1 year=[tex] \frac{(2000-x)*5*1}{100} [/tex]Interest earned by Account B=[tex] \frac{5(2000-x)}{100} [/tex]Total Interest Earned= Interest earned by Account A+ Interest earned by Account BTotal Interest Earned=[tex] \frac{3x}{100} [/tex]+[tex] \frac{5(2000-x)}{100} [/tex]75=[tex] \frac{3x}{100} [/tex]+[tex] \frac{10000-5x)}{100} [/tex]75=[tex] \frac{3x+10000-5x)}{100} [/tex]Multiply by 100 on both sides75*100=[tex] \frac{100(10000-2x))}{100} [/tex]7500=10000-2xLet us subtract 7500 from both sides7500-7500=10000-7500-2x0=2500-2xAdding 2x on both sides, we get0+2x=2500-2x+2x2x=2500To solve for x, divide by 2 on both sides2x/2=2500/2x=1250So, The Amount invested in Account A= $1250The Amount invested in Account B= $2000-1250=$750