Decide whether the pair of lines is parallel, perpendicular, or neither.3x - 6y = -13 and 18x + 9y = 5A) ParallelB) Perpendicular C) Neither

The lines are:  B) PerpendicularStep-by-step explanation:we have to convert both lines in slope-intercept form to find slopesSo,[tex]3x - 6y = -13\\-6y = -3x-13\\\frac{-6y}{-6} = \frac{-3x-13}{-6}\\\frac{-6y}{-6} = \frac{-3x}{-6}+\frac{-13}{-6}\\y = \frac{1}{2} +\frac{13}{6}[/tex]Let m1 be the slope of first line[tex]m_1 = \frac{1}{2}[/tex]For the second line:[tex]18x + 9y = 5\\9y = -18x+5\\\frac{9y}{9} = \frac{-18x+5}{9}\\\frac{9y}{9} = \frac{-18}{9}x+\frac{5}{9}\\y = -2x+\frac{5}{9}[/tex]Let m2 be the slope of line 2So,If the lines are parallel, their slopes are equalIf the lines are perpendicular, product of their slopes is -1We can see that[tex]\frac{1}{2} * -2 = -1[/tex]Hence,The lines are:  B) PerpendicularKeywords: Slopes, Parallel linesLearn more about slopes of lines at:brainly.com/question/4639731brainly.com/question/4655616#LearnwithBrainly