Drag each expression to show whether it is equivalent to 54x + 18, 18(3x – 1), or (6 • 9x) + (6 • 1). A.54x + 6 B(9 • 6x) – (9 • 2) C.54x – 18 18(3x + 1) D(6 • 9x) + (6 • 3) E.3(18x+2)
Question
Answer:
Answer:54x + 18 -> (6 • 9x) + (6 • 3) and 18(3x + 1)18(3x – 1) -> (9 • 6x) – (9 • 2) and 54x – 18(6 • 9x) + (6 • 1) -> 3(18x+2) and 54x + 6 Step-by-step explanation:Rewrite expressions, so that, we can compare them.
Distributing 18(3x – 1) gives
18(3x – 1) = 18*3x - 18*1 = 54x - 18
In 18(3x + 1) and 3(18x+2) we can perform similarly
18*(3x + 1) = 18*3x + 18*1 = 54x + 18
3*(18x+2) = 3*18x + 3*2 = 54x + 6
Multiplying each term inside parenthesis in (6*9x) + (6*1) gives
(6*9x) + (6*1) = 54x + 6
In (9*6x) – (9*2) and (6*9x) + (6*3) we can perform similarly
(9*6x) – (9*2) = 54x - 18
(6*9x) + (6*3) = 54x + 18
solved
general
11 months ago
4939