Find the volume of the solid obtained by rotating the region bounded by y=27x^3, y=0, x=1 about x=2

Hello,

[tex]V=\int_{0}^{27}\pi(2-x)^2dy\\\\ =\pi*\int_0^1(2-x)^2*81x^2dx\ since\ dy=27*3*x^2*dx\\\\ =\pi* \left[ \dfrac{4x^3}{3}- \dfrac{x^4}{2}+ \dfrac{x^5}{5} \right]_0^1\\\\ = \dfrac{31\pi}{30}[/tex]