Identify the equivalent expressions of 4(2x + x β 3) β 3x + 3 by applying x = 2 and x = 3.9x-99x-19x+x-99(x-1)4(3x-3)+3-3x
Question
Answer:
Well, first you want to input the values for x and see what the equations equals with each value. Remember order of operations!x=2
4(2*2 + 2 β 3) β 3(2) + 3
4(4 + 2 - 3) - 6 + 3
4(6 - 3) - 6 + 3
4(3) - 6 + 3
12 - 6 + 3
6 + 3 = 9
x=3
4(2*3 + 3 β 3) β 3(3) + 3
4(6 + 3 - 3) - 9 + 3
4(9 - 3) - 9 + 3
4(6) - 9 + 3
24 - 9 + 3
15 + 3 = 18
So, the equivalent expression should equal 9 when x is 2 and 18 when x is 3.
Lets plug them in!
9x-9
9(2) - 9 = 18 - 9 = 9
9(3) - 9 = 27 - 9 = 18
9x-1
9(2) - 1 = 18 - 1 = 17
9(3) - 1 = 27 - 1 = 26
9x+x-9
9(2) + 2 - 9 = 18 + 2 - 9 = 20 - 9 = 11
9(3) +3 - 9 = 27 + 3 - 9 = 30 - 9 = 21
9(x-1)
9(2-1) = 9(1) = 9
9(3-1) = 9(2) = 18
4(3x-3)+3-3x4(3*2 - 3) + 3 - 3(2) = 4(3) + 3 - 6 = 12 + 3 - 6 = 15 - 6 = 9
4(3*3 - 3) + 3 - 3(3) = 4(6) + 3 - 9 = 24 + 3 - 9 = 27 -9 =18
So, the equivalent expressions are
9x-9
9(x-1)
4(3x-3)+3-3x
Hope this helped! (Also, I meant expressions not equations! Oops!)
solved
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11 months ago
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