In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 11 feet long? x (to the nearest tenth) =

the complete question in the attached figure

we know that
if the weights are perfectly balanced
40*(x)=50*(11-x)
40x=550-50x------------> 50x+40x=550--------------> x=6.11

x=6.1 ft

the answer is 6.1 ft