P(x)P(x)P, (, x, )is a polynomial. P(x)P(x)P, (, x, )divided by (x+7)(x+7)(, x, plus, 7, )has a remainder of 555. P(x)P(x)P, (, x, )divided by (x+3)(x+3)(, x, plus, 3, )has a remainder of -4−4minus, 4. P(x)P(x)P, (, x, )divided by (x-3)(x−3)(, x, minus, 3, )has a remainder of 666. P(x)P(x)P, (, x, )divided by (x-7)(x−7)(, x, minus, 7, )has a remainder of 999. Find the following values of P(x)P(x)P, (, x, ). P(-3)=P(−3)=P, (, minus, 3, ), equals P(7)=P(7)=P, (, 7, ), equals

Answer:P(-3)=-4P(7) = 9Step-by-step explanation:Consider P(x) is a polynomial.According to the remainder theorem, if a polynomial, P(x), is divided by a linear polynomial (x - c), then the remainder of that division will be equivalent to f(c).Using the given information and remainder theorem we conclude,If P(x) is divided by  (x+7), then remainder is 5.⇒ P(-7)=5If P(x) is divided by  (x+3), then remainder is -4.⇒ P(-3)=-4If P(x) is divided by  (x-3), then remainder is 6.⇒ P(3)=6If P(x) is divided by  (x-7), then remainder is 9.⇒ P(7)=9Therefore, the required values are P(-3)=-4 and P(7) = 9.