Rework problem 28 from section 3.1 of your text, involving the inspection of refrigerators on an assembly line. You should still assume that no refrigerator has both too much and too little enamel; however, use the table below instead of that given in your book to answer the following questions.

Event: Probability: A. Too much enamel 0.18 B. Too little enamel 0.24 C. Uneven application 0.33 D. No defects noted 0.47 


let P(AC) = x, P(BC) = y, then P(A) + P(B) + P(C) - (x+y) = 1-0.47 = 0.53 x+y = 0.22 
3. The probability of paint defects that results to an improper amount of paint and uneven application? 
 P(A U B U C) = 0.53 

4. the probability of a paint defect that results to
the proper amount of paint, but uneven application?
P(C) - P(AC) - P(BC) = 0.47 - 0.22 = 0.25 


A and B are disjoint so P(ABC) = 0, but you can have P(AC) and P(BC). you can't compute these separately here, but you can compute P(AC) + P(BC). By the way, P(AC) eg is just an abbreviated version of P(A∩C).