sarah wants to put three paintings on her living room wall. the length of the wall is 15 feet longer than its width. the length and width of the paintings are 3 feet and 4 feet, respectively. which of the following inequalities can be used to solve for x, if sarah wants the combined area of the wall and the paintings to be at the most 202 feet square feet?

Let
x-----------> the width of the wall
x+15------> the length of the wall 

we know that
x*(x+15)+3*[3*4] <=202 ft²
x²+15x+36 <=202
x²+15x+36 -202<=0
x²+15x-166<=0

the answer is 
x²+15x-166<=0

using a graph tool
see the attached figure
The maximum value of x is x=7.408 ft