The area of the base of the regular quadrilateral pyramid is 36 cm2 and the area of a lateral face is 48 cm2. Find: Surface area of the pyramid

Answer:The surface area of the pyramid is [tex]228\ cm^{2}[/tex]Step-by-step explanation:we know thatThe surface area of the Pyramid is equal to[tex]SA=B+LA[/tex]whereB is the area of the base of the pyramidLA is the lateral area of the pyramidIn this problem we have[tex]B=36\ cm^{2}[/tex]Find the lateral area LARemember that the lateral area is the area of its four lateral facessoMultiply the area of a lateral face by 4 (because is a regular quadrilateral)[tex]LA=(4)(48)=192\ cm^{2}[/tex]Find the surface area SAsubstitute the values[tex]SA=36+192=228\ cm^{2}[/tex]