The coordinates of square ABCD are A(0, 0) , B(a, 0) , C(blank, a), and D(0,blank ).The slope of AC, when simplified, is equal to blank .The slope of BD, when simplified, is equal to −1 .The product of the slopes is equal to blank .Therefore, AC is perpendicular to BD.please fill in the blank spots

The coordinates of square ABCD are A(0, 0) , B(a, 0) , C(blank, a), and D(0,blank ).

square, all sides are equal so side = a
A(0, 0) , B(a, 0) , C(a, a), and D(0,a).

The slope of AC = (a-0)/(a-0) = a/a = 1
The slope of BD, when simplified, is equal to −1

The product of the slopes = 1(-1) = -1

Therefore, AC is perpendicular to BD.