The coordinates of the vertices of △ABC are A(−4, 6) , B(−2, 2) , and C(−6, 2) .The coordinates of the vertices of △A′B′C′ are A′(2, 6) , B′(0, 2) , and C′(4, 2) .Drag and drop the answers into the boxes to correctly complete the statement.A sequence of transformations that maps △ABC to △A′B′C′ is a blank followed by a blank.translation 2 units leftreflection across the x-axisreflection across the y-axistranslation 2 units down

Answer-The sequences of transformations that maps △ABC to △A′B′C′ areReflection across the y-axisTranslation 2 units leftSolution-The coordinates of the vertices of ΔABC are A = (−4, 6) B = (−2, 2)C = (−6, 2)The coordinates of the vertices of ΔA′B′C′ are A′ = (2, 6)B′ = (0, 2)C′ = (4, 2)As all the y-coordinates of all the function are same, so the triangle is neither translated up or down (∵ (x, y) → (x, y±k)), nor reflected over x-axis(∵ (x, y) → (x, -y)).As the signs of x-coordinate is changed, it might be reflected over y axis,Rule for reflection over y axis is,(x, y) → (-x, y)so,A" = (4, 6) B" = (2, 2)C" = (6, 2)As the x-coordinates of vertices of ΔA′B′C′ are 2 units less than that of ΔA"B"C"So it is then translated 2 units left.Therefore, the sequences of transformations that maps △ABC to △A′B′C′ areReflection across the y-axisTranslation 2 units left