The length of the rectangle garden is three feet less than twice its width. If the perimeter of the garden is 42 feet, what is its length? ( 10marks)

Answer:13 feetStep-by-step explanation:You are given that the perimeter, P, of the rectangle is 42 meters (i.e., P = 42). Also, the length, L, of the rectangle is 3 meters less than 2 times the width, W (i.e., L = 2W - 3). Recall that the perimeter, P, of a rectangle is given by the following formula:     P = 2W + 2L Substituting 2W - 3 for L, we arrive at the following:    P = 2W + 2(2W - 3)    P = 2W + 2·2W + 2·-3      P = 2W + 4W - 6    P = 6W - 6 Since we were given that  P = 42, then     42 = 6W - 6     42 + 6 = 6W - 6 + 6     48 = 6W     48/6 = 6W/6     8 = W Therefore, the width of the rectangle is 8 meters. Use this value to solve for the length:     L = 2W - 3     L = 2·8 - 3     L = 16 - 3     L = 13