The pair of points is on the graph of an inverse variation. Find the missing value. (1.6, 6) and (8, y) 0.03 30 1.2 0.83

one may note that (1.6 , 6)  is just another way to say x = 1.6 when y = 6.

and that (8 , y) is another way to say x = 8 and y is who knows.

[tex]\bf \qquad \qquad \textit{inverse proportional variation}\\\\ \textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ -------------------------------[/tex]

[tex]\bf \textit{we know that } \begin{cases} x=1.6\\ y=6 \end{cases}\implies 6=\cfrac{k}{1.6}\implies 6(1.6)=k\implies 9.6=k \\\\\\ \qquad therefore\qquad \boxed{y=\cfrac{9.6}{x}} \\\\\\ \textit{when x = 8, what is \underline{y}?}\qquad y=\cfrac{9.6}{8}[/tex]