The table of values represents a quadratic function.What is the average rate of change for f(x) from x = 0 to x = 10 ? x f(x)−10 184−5 390 −65 4910 204
Question
Answer:
(f(10) -f(0))/(10 -0) = (204 -(-6))/10 = 21The average rate of change on the interval is 21.
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