What are the solutions of the equation x4 β 5x2 β 14 = 0? Use factoring to solve
Question
Answer:
(x2 - ) (x2 + ) = 0(x2 - 7) (x2 + 2) = 0
(x2 - 7) = 0 and (x2 + 2) = 0
x2 = 7 and x2 = - 2
βx2 = β7 and βx2 = β-2
x = β7 and x = β-2 --> it doesn't exist
solved
general
11 months ago
3091