What is the area of this figure?Enter your answer in the box.units²

Given is the irregular hexagon. We can divide the given figure into two triangles and one rectangle, and then find areas of each, and then add all of them to find the final answer. We can find the dimensions by counting the blocks on graph. Given two triangles are identical in shape with base (b=7) and height (h=2). The area of triangle [tex] =\frac{1}{2} bh = \frac{1}{2} (7)(2) = 7 [/tex] squared units. Area of two triangles = 14 squared units. Rectangle has length (l) same as base (b) of triangle i.e. l=7 and width (w=4). Area of rectangle = l × w = 7 × 4 = 28 squared units. Total area = 14 + 28 = 42 squared units. So, final answer is 42 squared units.