Which of these is a point-slope equation of the line that is perpendicular to y-3=4(x-10) and passes through(-3,7)A. y+7=4(x-3)B. y-7= -1/4(x+3)C. y+7= -1/4(x-3)D. y-7= -4x(x+3)

Try this option:
1. rule: if y+a₁=k₁(x+b₁) ⊥ y+a₂=k₂(x+b₂), then k₁*k₂= -1.
for unknown line k= -1/4.
2. substituting the coordinates (-3;7) into the equations, it is possible to find that 'y-7' and 'x+3'.
3. at the end, if to make up the equation: y-7= -1/4(x+3).

Answer: B