Write z=-6+6i in polar form
Question
Answer:
z=r(cosα +i*sinα)r=√(6²+6²)=√(36+36)=√(2*36)=6√2
tanα=6/-6=-1, α=135⁰, or α=3π/4 (if you need in π)
z=6√2(cos 135+i*sin 135)
or
z=6√2(cos 3π/4+i*sin 3π/4)
solved
general
11 months ago
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