x/3≤2-x/9 solve and give answers in interval notation.

Question

Answer:

Multiply both sides of the inequality by $9$

$3x \leq 18-x$

Move the variable to the left-hand side and change its sign

$3x+x \leq 18$

Collect like terms

$4x \leq 18$

Divide both sides of the inequality by $4$

$\begin{align*}&x \leq \frac{ 9 }{ 2 } \\&\begin{array} { l }\begin{array} { l }\begin{array} { l }x \leq 4 \frac{ 1 }{ 2 },& x \leq 4.5\end{array},& x \in \left\langle-\infty, \frac{ 9 }{ 2 }\right]\end{array},& \left\{ \right\}\end{array}\end{align*}$

solved

general 11 months ago 163