x+y+z=1 -2x+4y+6z=2-x+3y-5z=11Solved using elimination

Answer: x = 0y = 2z = -1Step-by-step explanation:The system of equations arex+y+z=1 - - - - - - - - - - 1-2x+4y+6z=2 - - - - - - - - - 2-x+3y-5z=11 - - - - - - - - - 3Step 1We would eliminate x by adding equation 1 to equation 3. It becomes4y -4z = 12 - - - - - - - - - 4Step 2We would multiply equation 1 by 2. It becomes2x + 2y + 2z = 2 - - - - - - - - - 5We would add equation 2 and equation 5. It becomes6y + 8z = 4 - - - - - - - - - 6Step 3We would multiply equation 4 by 6 and equation 6 by 4. It becomes24y - 24z = 72 - - - - - - - - 724y + 32z = 16 - - - - - - - - 8We would subtract equation 8 from equation 7. It becomes-56z = 56z = -56/56 = -1Substituting z = -1 into 7, it becomes24y - 24×-1 = 7224y + 24 = 7224y = 72 - 24 = 48y = 48/24 = 2Substituting y = 2 and z = -1 into equation 1, it becomesx + 2 - 1 = 1 x = 1 - 1 = 0