Five times the difference of twice a number and seven is negative twenty-five. Find the number.

The number is 1Step-by-step explanation:Let x be the required numberThen according to given statementFive times the difference of twice a number and seven is negative twenty-five.[tex]5(2x-7) = -25[/tex]Simplifying[tex]10x-35 = -25\\[/tex]Adding 35 on both sides[tex]10x-35+35 = -25+35\\10x = 10[/tex]Dividing both sides by 10[tex]\frac{10x}{10} = \frac{10}{10}\\x = 1[/tex]Verification:[tex]5[2(1)-7] = -25\\5(2-7) = -25\\5(-5) = -25\\-25=-25[/tex]Hence,1 is the numberKeywords: Linear equationLearn more about linear equation at:brainly.com/question/4706270brainly.com/question/4710621#LearnwithBrainly