The plane still climbed in altitude after the bird strike even after they lost thrust on both engines for 19 more seconds reaching a maximum height of 3060 feet.If the plane climbed 242 more feet at an angle of 2 degrees. How much further did the plane travel to reach its maximum height in miles

Answer:1.31 miles Step-by-step explanation:If the plane travel at the inclined direction to reach its maximum height of 3060 feet, then the horizontal plane and the inclined plane makes an angle of 2° with each other. If we imagine the inclined plane as the hypotenuse of a right triangle and the vertical height it climbs is the perpendicular of the triangle. Therefore, using trigonometry of a right triangle  [tex]\sin 2 = \frac{\textrm {Verticle height}}{\textrm {Incined path traveled}} = \frac{242}{\textrm {Incined path traveled}}[/tex]  {Since the plane climbed 242 feet at that inclination} ⇒ [tex]\textrm {Incined path traveled} = \frac{242}{ \sin 2} = 6934.19[/tex] feet.  Therefore, the plane traveled 6934.19 feet i.e. [tex]\frac{6934.19}{5280} = 1.31[/tex] miles farther to reach its maximum height. {Since, 1 mile = 5280 feet} (Answer)