A student solved the following problem and made an error:Triangles ABC and DEF. Angles A and F are congruent and measure 63 degrees. Coordinates for the vertices are at A 1, 2 and B 1, 4 and C 3, 3 and D 5, 1 and E 3, 2 and F 5, 3.Line 1 segment AB equals 2, segment FD equals 2, segment AB is congruent to segment FDLine 2 ∠A ≅ ∠FLine 3 Length of segment AC.A (1, 2)C (3, 3)d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, then d equals square root of quantity 1 minus 3 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1 squared, then d equals square root of 4 plus 1, then d equals square root of 5segment AC = 2.23Line 4 Length of segment EF.E (3, 2)F (5, 3)d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared then d equals square root of quantity 3 minus 5 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1, then d equals square root of 4 plus 1, then d equals square root of 5segment EF= 2.23Line 5 segment AC is congruent to segment FELine 6 triangle ABC is congruent to triangle EFDby SASIn which line did the student make the first mistake? Line 1 Line 5 Line 6 Line 2

Question
solved
general 11 months ago 8718

5. Triangle ABC is a right triangle with CD and AB angle C is a right triangle. By the ,(.......) △ACB∼△ADC and △ACB∼△CDB. Since similar triangles have (........) sides, BCBA=BDBC and ACAB=ADAC . Using cross multiplication gives the equations (BC)2=(BD)(BA) and (AC)2=(AD)(AB). Adding these together gives (BC)2+(AC)2=(BD)(BA)+(AD)(AB). Factoring out the common segment gives (BC)2+(AC)2=(AB)(BD+AD). Using (........) gives (BC)2+(AC)2=(AB)(AB), which simplifies to (BC)2+(AC)2=(AB)2 .First paranthese SAS or AAS or SSSSecond parantheseCongruent or proportionalThird parantheseSA or CPCTC

Question
solved
general 11 months ago 8253